3.Stream的filter与谓语逻辑
最后更新于：2022-04-02 07:57:20
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```[youku]
XNDU5Nzk4MTgwMA
```
## 一、基础代码准备
建立一个实体类，该实体类有五个属性。下面的代码使用了lombok的注解Data、AllArgsConstructor，这样我们就不用写get、set方法和全参构造函数了。lombok会帮助我们在编译期生成这些模式化的代码。
~~~
@Data
@AllArgsConstructor
public class Employee {
private Integer id;
private Integer age; //年龄
private String gender; //性别
private String firstName;
private String lastName;
}
~~~
写一个测试类，这个测试类的内容也很简单，新建十个Employee 对象
~~~
public class StreamFilterPredicate {
public static void main(String[] args){
Employee e1 = new Employee(1,23,"M","Rick","Beethovan");
Employee e2 = new Employee(2,13,"F","Martina","Hengis");
Employee e3 = new Employee(3,43,"M","Ricky","Martin");
Employee e4 = new Employee(4,26,"M","Jon","Lowman");
Employee e5 = new Employee(5,19,"F","Cristine","Maria");
Employee e6 = new Employee(6,15,"M","David","Feezor");
Employee e7 = new Employee(7,68,"F","Melissa","Roy");
Employee e8 = new Employee(8,79,"M","Alex","Gussin");
Employee e9 = new Employee(9,15,"F","Neetu","Singh");
Employee e10 = new Employee(10,45,"M","Naveen","Jain");
List employees = Arrays.asList(e1, e2, e3, e4, e5, e6, e7, e8, e9, e10);
List filtered = employees.stream()
.filter(e -> e.getAge() > 70 && e.getGender().equals("M"))
.collect(Collectors.toList());
System.out.println(filtered);
}
}
~~~
需要注意的是上面的filter传入了lambda表达式(之前的章节我们已经讲过了)，表达过滤年龄大于70并且男性的Employee员工。输出如下：
~~~
[Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin)]
~~~
## 二、什么是谓词逻辑？
下面要说我们的重点了，通过之前的章节的讲解，我们已经知道lambda表达式表达的是一个匿名接口函数的实现。那具体到Stream.filter()中，它表达的是什么呢？看下图：可以看出它表达的是一个Predicate接口，在英语中这个单词的意思是：谓词。
### **什么是谓词？（百度百科）**
### 什么是谓词逻辑？
WHERE 和 AND 限定了主语employee是什么，那么WHERE和AND语句所代表的逻辑就是谓词逻辑
~~~
SELECT *
FROM employee
WHERE age > 70
AND gender = 'M'
~~~
## 三、谓词逻辑的复用
通常情况下，filter函数中lambda表达式为一次性使用的谓词逻辑。如果我们的谓词逻辑需要被多处、多场景、多代码中使用，通常将它抽取出来单独定义到它所限定的主语实体中。
比如：将下面的谓词逻辑定义在Employee实体class中。
~~~
public static Predicate ageGreaterThan70 = x -> x.getAge() >70;
public static Predicate genderM = x -> x.getGender().equals("M");
~~~
### 3.1.and语法（交集）
~~~
List filtered = employees.stream()
.filter(Employee.ageGreaterThan70.and(Employee.genderM))
.collect(Collectors.toList());
~~~
输出如下：
~~~
[Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin)]
~~~
### 3.2.or语法（并集）
~~~
List filtered = employees.stream()
.filter(Employee.ageGreaterThan70.or(Employee.genderM))
.collect(Collectors.toList());
~~~
输出如下：实际上就是年龄大于70的和所有的男性（由于79的那位也是男性，所以就是所有的男性）
~~~
[Employee(id=1, age=23, gender=M, firstName=Rick, lastName=Beethovan), Employee(id=3, age=43, gender=M, firstName=Ricky, lastName=Martin), Employee(id=4, age=26, gender=M, firstName=Jon, lastName=Lowman), Employee(id=6, age=15, gender=M, firstName=David, lastName=Feezor), Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin), Employee(id=10, age=45, gender=M, firstName=Naveen, lastName=Jain)]
~~~
### 3.3.negate语法（取反）
~~~
List filtered = employees.stream()
.filter(Employee.ageGreaterThan70.or(Employee.genderM).negate())
.collect(Collectors.toList());
~~~
输出如下：把上一小节代码的结果取反，实际上就是所有的女性
~~~
[Employee(id=2, age=13, gender=F, firstName=Martina, lastName=Hengis), Employee(id=5, age=19, gender=F, firstName=Cristine, lastName=Maria), Employee(id=7, age=68, gender=F, firstName=Melissa, lastName=Roy), Employee(id=9, age=15, gender=F, firstName=Neetu, lastName=Singh)]
~~~
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