Java 实例 – 利用堆栈将中缀表达式转换成后缀表达式

最后更新于:2022-03-27 01:05:37

Java 实例 – 利用堆栈将中缀表达式转换成后缀表达式

Java 实例 – 利用堆栈将中缀表达式转换成后缀表达式 Java 实例

以下实例演示了如何使用堆栈进行表达式的堆栈将中缀(Infix)表达式转换成后缀(postfix)表达式:

InToPost.java 文件

import java.io.IOException;

public class InToPost {
private Stack theStack;
private String input;
private String output = "";
public InToPost(String in) {
input = in;
int stackSize = input.length();
theStack = new Stack(stackSize);
}
public String doTrans() {
for (int j = 0; j < input.length(); j++) {
char ch = input.charAt(j);
switch (ch) {
case +:
case :
gotOper(ch, 1);
break;
case *:
case /:
gotOper(ch, 2);
break;
case (:
theStack.push(ch);
break;
case ):
gotParen(ch);
break;
default:
output = output + ch;
break;
}
}
while (!theStack.isEmpty()) {
output = output + theStack.pop();
}
System.out.println(output);
return output;
}
public void gotOper(char opThis, int prec1) {
while (!theStack.isEmpty()) {
char opTop = theStack.pop();
if (opTop == () {
theStack.push(opTop);
break;
}
else {
int prec2;
if (opTop == + || opTop == )
prec2 = 1;
else
prec2 = 2;
if (prec2 < prec1) {
theStack.push(opTop);
break;
}
else
output = output + opTop;
}
}
theStack.push(opThis);
}
public void gotParen(char ch){
while (!theStack.isEmpty()) {
char chx = theStack.pop();
if (chx == ()
break;
else
output = output + chx;
}
}
public static void main(String[] args)
throws IOException {
String input = "1+2*4/5-7+3/6";
String output;
InToPost theTrans = new InToPost(input);
output = theTrans.doTrans();
System.out.println("Postfix is " + output + \n);
}
class Stack {
private int maxSize;
private char[] stackArray;
private int top;
public Stack(int max) {
maxSize = max;
stackArray = new char[maxSize];
top = –1;
}
public void push(char j) {
stackArray[++top] = j;
}
public char pop() {
return stackArray[top];
}
public char peek() {
return stackArray[top];
}
public boolean isEmpty() {
return (top == –1);
}
}
}

以上代码运行输出结果为:

124*5/+7-36/+
Postfix is 124*5/+7-36/+

Java 实例 – 利用堆栈将中缀表达式转换成后缀表达式 Java 实例