C 语言实例 – 实现简单的计算器

最后更新于：2022-03-27 02:17:42

C 语言实例 – 实现简单的计算器

C 语言实例 – 实现简单的计算器 C 语言实例

实现加减乘除计算。

实例

# include <stdio.h>

int main() {

char operator;
double firstNumber,secondNumber;

printf("输入操作符 (+, -, *,): ");
scanf("%c", &operator);

printf("输入两个数字: ");
scanf("%lf %lf",&firstNumber, &secondNumber);

switch(operator)
{
case ‘+’:
printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);
break;

case ‘-‘:
printf("%.1lf – %.1lf = %.1lf",firstNumber, secondNumber, firstNumber – secondNumber);
break;

case ‘*’:
printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
break;

case ‘/’:
printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber);
break;

// operator doesn’t match any case constant (+, -, *, /)
default:
printf("Error! operator is not correct");
}

return 0;
}

输出结果为：

输入操作符 (+, -, *,): *
输入两个数字: 4 5
4.0 * 5.0 = 20.0

C 语言实例 – 实现简单的计算器 C 语言实例