Python 简单计算器实现
最后更新于：2022-03-27 01:12:04
Python 简单计算器实现
Python3 实例以下代码用于实现简单计算器实现，包括两个数基本的加减乘除运算：
实例(Python 3.0+)
# Filename : test.py
# author by : docs.gechiui.com/w3school # 定义函数
def add(x, y):
"""相加"""
"""相减"""
"""相乘"""
"""相除"""
print("选择运算：")
print("1、相加")
print("2、相减")
print("3、相乘")
print("4、相除") choice = input("输入你的选择(1/2/3/4):") num1 = int(input("输入第一个数字: "))
num2 = int(input("输入第二个数字: ")) if choice == ‘1‘:
print(num1,"+",num2,"=", add(num1,num2)) elif choice == ‘2‘:
print(num1,"–",num2,"=", subtract(num1,num2)) elif choice == ‘3‘:
print(num1,"*",num2,"=", multiply(num1,num2)) elif choice == ‘4‘:
print(num1,"/",num2,"=", divide(num1,num2))
else:
print("非法输入")
# author by : docs.gechiui.com/w3school # 定义函数
def add(x, y):
"""相加"""
return x + y def subtract(x, y):
"""相减"""
return x – y def multiply(x, y):
"""相乘"""
return x * y def divide(x, y):
"""相除"""
return x / y # 用户输入
print("选择运算：")
print("1、相加")
print("2、相减")
print("3、相乘")
print("4、相除") choice = input("输入你的选择(1/2/3/4):") num1 = int(input("输入第一个数字: "))
num2 = int(input("输入第二个数字: ")) if choice == ‘1‘:
print(num1,"+",num2,"=", add(num1,num2)) elif choice == ‘2‘:
print(num1,"–",num2,"=", subtract(num1,num2)) elif choice == ‘3‘:
print(num1,"*",num2,"=", multiply(num1,num2)) elif choice == ‘4‘:
print(num1,"/",num2,"=", divide(num1,num2))
else:
print("非法输入")
执行以上代码输出结果为：
选择运算： 1、相加 2、相减 3、相乘 4、相除 输入你的选择(1/2/3/4):2 输入第一个数字: 5 输入第二个数字: 2 5 - 2 = 3